Remember (or maybe you don’t) how it’s easy to factor trinomials when the coefficient of the x2 term is one? But it gets a lot more complicated when that number is something bigger. I was taught basically to make successive guesses until I found what works. But Fred showed me this way--
Consider 3 (the coefficient of x2) and 6 (the constant term).
Which of their factors, when recombined into 2 new numbers, will add to 11 (the coefficient of x)?
3=1*3
6=2*3 or 1*6
Recombining those factors, I get 1*2=2 and 3*3=9. The sum of 2 and 9 is 11.
(I didn’t use the factors 1*6 because they don’t combine with the factors of 3 to get 11.)
Now rewrite the problem: 3x2 + 9x + 2x + 6.
(This is exactly the same as above, but the 11x is split into 9x + 2x.)
Find the common factor in the first two terms, then in the second two:
3x(x + 3) + 2(x + 3)
Find the common factor again. It is (x + 3):
(x + 3)(3x + 2)
Done! You have to factor twice, but it’s much easier than the guessing game I learned in my algebra classes.
This algebra book is the only one I have used from the Life of Fred. As I mentioned, it has been a good fit for my daughter. It is the only math series I know of that is "whole to parts." I feel, however, that there are some places where Fred moves too quickly. There have been a few times when I have supplemented with additional explanation. I also highly recommend the Fred Companion book for this same reason; it helps to pace one’s progression through the chapters, and it offers more problems for extra practice.
My oldest daughter will graduate in maths at uni. Throughout her homeschool life I don't think I could ever give her enough Maths and even now she talks in a "different" language(ie maths) to me.
ReplyDeleteIf you are interested here is the link to a post I wrote about the language of maths
http://homeschoolingdownunder.blogspot.com/2008/06/telling-mathematical-tales.html